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17 February, 13:34

Find the values for A and B that would make the equality true

-5 (3x^2+5x+b) = ax^2-25x+45

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Answers (2)
  1. 17 February, 14:37
    0
    a = - 15 and b = - 9

    Step-by-step explanation:

    distribute the left side

    - 15x² - 25x - 5b

    For - 15x² - 25x - 5b = ax² - 25x + 45

    Then the coefficients of like terms must be equal, hence

    comparing coefficients of x² term ⇒ a = - 15

    comparing constant term ⇒ - 5b = 45 ⇒ b = - 9
  2. 17 February, 17:03
    0
    Answer: a = - 15, b = - 9

    Step-by-step explanation:

    -5 (3x² + 5x + b) = ax² - 25x + 45

    -15x² - 25x - 5b = ax² - 25x + 45 distributed - 5 on left side

    Notice that the middle terms (-25x) are equal, so the the remaining terms will also be equal.

    -15x² = ax² ⇒ - 15 = a

    -5b = 45 ⇒ b = - 9
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