Two identical rubber balls are dropped from different heights. Ball 1 is dropped from a height of 148 ft, and ball 2 is dropped from a height of 203 feet. Use thr function f (t) = - 16t^2+h to determine the current height, f (t), a ball is dropped from a height h, over a given time t.

When does ball 1 reach the ground? Round to the nearest hundredth.

3.04 seconds

Step-by-step explanation:

f (t) = - 16t² + h

Ball 1 is dropped from a height of 148 feet, so h = 148. When the ball reaches the ground, f (t) = 0.

0 = - 16t² + 148

16t² = 148

t² = 9.25

t ≈ 3.04

3.04 seconds

Step-by-step explanation:

Two identical rubber balls are dropped from different heights. Ball 1 is dropped from a height of 148 ft, and ball 2 is dropped from a height of 203 feet. Using the function f (t) = - 16t^2+h to determine the current height, f (t), a ball is dropped from a height h, over a given time t, ball 1 reaches the ground in 3.04 seconds.