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13 November, 07:10

Chloe and Charlie are taking a trip to the pet store to purchase some items for their new puppy they know that they need a bag of food that cost $7 and they also want toys that are $2 each. If chloe has 30$ and her friends has 1/3 of the amounts what is the maximum number of toy they can get

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  1. 13 November, 09:20
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    Answer: the maximum number of toy they can get is 16.

    Step-by-step explanation:

    If chloe has $30 and her friend has 1/3 of the amount, it means that the amount that her friend has is

    1/3 * 30 = $10

    The total amount that they have is

    30 + 10 = $40

    They need a bag of food that cost $7 and they also want toys that are $2 each.

    Let x represent the number of toys that they want to get. The total cost of a bag of food and x toys is

    7 + 2x

    Since they have $40, then the expression would be

    7 + 2x ≤ 40

    2x ≤ 40 - 7

    2x ≤ 33

    x ≤ 33/2

    x ≤ 16.5

    Since the number of toys cannot be a fraction, then the maximum number of toy they can get is 16
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