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12 September, 22:26

Verify the identity secx-secx sin^2x=cosx

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  1. 12 September, 22:42
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    Hello:

    * secx = 1/cosx

    cos²x+sin²x = 1

    **sin²x = 1-cos²x

    by (*):

    secx-secx sin²x = (1/cosx) - (1/cosx) sin²x

    = (1/cosx) (1 - sin²x) ... factory : (1/cosx)

    by (**)

    secx-secx sin²x = (1/cosx) cos²x

    secx-secx sin²x = cosx ... (simplify by : cosx)
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