Ask Question
25 August, 04:56

A hyperbola centered at the origin has vertices at (± √33,0) and foci at (± √59,0).

Write the equation of this hyperbola.

+1
Answers (1)
  1. 25 August, 07:32
    0
    x^2/33 + y^2/26 = 1

    Step-by-step explanation:

    The formula for a hyperbola centered at the origin is:

    x^2/a^2 - y^2/b^2 = 1

    The vertices are located at (±a, 0), so we have that the value of a is √33

    The foci are located at (±c, 0), where c^2 = a^2 + b^2

    So if we have that c = √59, we can find the value of b:

    59 = 33 + b^2

    b^2 = 26

    b = √26

    So the formula for this hyperbole is:

    x^2/33 + y^2/26 = 1
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “A hyperbola centered at the origin has vertices at (± √33,0) and foci at (± √59,0). Write the equation of this hyperbola. ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers