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21 April, 12:06

What are the x-intercepts of the function f (x) = - 2x2 - 3x + 20? (-4, 0) and five-halves five-halves and (4, 0) (-5, 0) and (2, 0) (-2, 0) and (5, 0)

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  1. 21 April, 13:22
    0
    (-4, 0) and (5/2, 0)

    Step-by-step explanation:

    f (x) = - 2x2 - 3x + 20

    factor using the diamond method

    -2*20 = - 40

    so - 8 * 5 = - 40 and - 8 + 5 = - 3 so ...

    f (x) = - 2x^2 - 8x + 5x + 20

    f (x) = - 2x (x + 4) + 5 * (x + 4)

    f (x) = (-2x + 5) * (x + 4)

    x-intercepts are x = 5/2 and x = -4

    (-4, 0) and (5/2, 0)
  2. 21 April, 16:00
    0
    (-4, 0) and (5/2, 0)
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