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5 October, 18:52

How far apart are the foci of an ellipse with a major axis of 10 feet and a minor axis of 6 feet?

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Answers (2)
  1. 5 October, 19:09
    0
    The focii are 8 feet apart

    Step-by-step explanation:

    You can use the formula

    F = √ (a^2 - b^2) where F is the distance of the focii from the center, a = length of the semi major axis and b = length of the semi minor axis)

    So here it is √ (5^2 - 3^2)

    = √16 = 4

    So the distance is 2*4 = 8
  2. 5 October, 22:22
    0
    Quadratic relations and comic sections unit test part 1

    12. b. 8 feet

    1. b ellipse

    domain - 4<=x<=4

    range - 3<=y<=3

    2. c. x^2/3

    3. c. 1/10 x^2

    4. b. 5 inches

    5. d. x=1/12 (y-4) ^2 + 2

    6. b. (x-4) ^2 + (y-5) ^2 = 49

    7. b. (x+8) ^2 + (y+4) ^2 = 25

    8. d. (x+3) ^2 + (y+2) ^2 = 9

    9. a. center at (7,-6); radius 4

    10. b. x^2/25 + y^2/169 = 1

    11. a. (0, + / - 6)

    12. b. 8 ft

    13. c. (put equation in graphing calculator to see graph)

    14. d. (0, + / -5)
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