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19 March, 23:46

Given the Arithmetic sequence A 1, A 2, A 3, A 4 32, 42, 52, 62 What is the value of A16?

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  1. 20 March, 00:02
    0
    a16 = 148

    Step-by-step explanation:

    There are other ways to do this, but the simplest way to get to a1 is just to subtract two terms you know to get d.

    a6 - a5 = 42 - 32 = 10

    so a4 = a6 - a5 = 42 - 32 = 10

    a4 = 32 - 10 = 22 [a5 - 10]

    a3 = 22 - 10 = 12 [a4 - 10]

    a2 = 12 - 10 = 2 [a3 - 10]

    a1 = 2 - 10 = - 8 [a2 - 10]

    Givens

    a1 = - 8

    d = 10

    Term number = n = 16

    Formula

    an = a1 + (n - 1) * d

    Solution

    n = 16

    a1 = - 2

    d = 10

    a16 = - 2 + (16 - 1) * 10

    a16 = - 2 + 15*10

    a16 = - 2 + 150

    a16 = 148
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