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7 November, 23:19

Given right triangle jkl, what is the value of cos (l) ?

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  1. 8 November, 02:27
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    Taking K as the right angle = >

    cos (L) = segment LK / hypotenuse

    => cos (L) = segment LK / √ [ (segment LK) ^2 + (segment KJ) ^2 ]
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