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2 January, 01:04

Which system of equations has exactly one solution?

A.) 2 x minus 4 y = 8. x + y = 7.

B.) 3 x + y = negative 1. 6 x + 2 y = negative 2.

C.) 3 x + 3 y = 3. Negative 6 x minus 6 y = 3.

D.) 3 x minus 2 y = 4. Negative 3 x + 2 y = 4.

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Answers (2)
  1. 2 January, 04:24
    0
    A.) 2 x minus 4 y = 8. x + y = 7.

    Step-by-step explanation:

    A.) 2 x minus 4 y = 8. x + y = 7.

    2x - 4y = 8

    x - 2y = 4

    x = 4 + 2y

    x + y = 7

    4 + 2y + y = 7

    3y = 3

    y = 1

    x = 4 + 2

    x = 6

    Only solution: (6,1)
  2. 2 January, 04:28
    0
    A.) 2 x minus 4 y = 8. x + y = 7.

    Step-by-step explanation:

    A.) 2 x minus 4 y = 8. x + y = 7.

    2x-4y = 8

    x+y=7

    This has one solution

    B.) 3 x + y = negative 1. 6 x + 2 y = negative 2.

    3x+y = - 1

    Multiply by 2

    6x + 2y = - 2

    This is the second equation so it has infinite solutions

    C.) 3 x + 3 y = 3. Negative 6 x minus 6 y = 3.

    3x+3y = 3

    Multiply by - 2

    -6x-6y = - 6

    The equation is the same but the constant, which means they are parallel lines, they have zero solutions

    D.) 3 x minus 2 y = 4. Negative 3 x + 2 y = 4.

    3x - 2y = 4

    Multiply by - 1

    -3x + 2y = - 4

    The equation is the same but the constant, which means they are parallel lines, they have zero solutions
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