Solving systems by elimination 3x + 4y equals - 3 5x + 3y equals 6

3x+4y=-3 ... (1)

5x+3y=6 ... (2)

So we multiply equation 1 by 5 and 2 by 3 and subtracting, we got

15x+20y=-15

15x+9y=18

(-) (-) (-)

11y=-33

y=-3

Putting y=-3 in equation 1, we have 3x-12=-3

3x=9

x=3

So x=3 (Ans)

y=-3 (Ans)

Move all terms that don't contain x to the right side and solve.

x=-1 - 4y/3

Move all terms that don't contain x to the right side and solve.

x=6/5 - 3y/5