How do you find the domain of f (x) = x over 2x^2-5x-3

D = ]-∞, - 1/2[ U ]-1/2, 3[ U ]3, + ∞[

Step-by-step explanation:

hello:

f (x) = x / (2x²-5x-3)

f exist for : 2x²-5x-3 ≠ 0

2x²-5x-3 = 0

∆ = b² - 4ac a=2 and b = - 5 and c = - 3

∆ = (-5) ² - 4 (2) (-3) = 49 = 7²

X1 = (-b-√∆) / 2a = (5-7) / 4 = - 1/2

X2 = (-b+√∆) / 2a = (5+7) / 4 = 3

the domain is : D = ]-∞, - 1/2[ U ]-1/2, 3[ U ]3, + ∞[

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