The length of a rectangle is seven less than twice the length of its width. If the area of the rectangle is 15 square meters, find the value of x.

Length = 3mWidth = 5mState where x is accordingly.

The length of a rectangle is seven less than twice the length of its width.

L = 2W - 7

A = W * L

A = 15

15 = W * L

Substitute the L in terms of W

15 = W * (2W - 7)

15 = 2W^2 - 7W

2W^2 - 7W - 15 = 0

Factorise:

(2W + 3) (W - 5) = 0

Solve for W:

2W + 3 = 0

2W = 0 - 3

2W = 3

W = 3/2

W = 1.5

W - 5 = 0

W = 0 + 5

W = 5

Use the original equation to find L:

L = 2W - 7

L = 2 (5) - 7

L = 10 - 7

L = 3

L * W = 15

3 * 5 = 15