The sum of two numbers is 8and the sum of their squares is 34. What is the smaller number?

Step-by-step explanation:

let the numbers be x, y

x+y=8

y=8-x

x²+y²=34

x² + (8-x) ²=34

x²+64+x²-16x=34

2x²-16x+64-34=0

2x²-16x+30=0

x²-8x+15=0

1*15=15

5+3=8

5*3=15

x² - (3+5) x+15=0

x²-3x-5x+15=0

x (x-3) - 5 (x-3) = 0

(x-3) (x-5) = 0

either x=3 or 5

if x=3, y=8-3=5

if x=5, y=8-5=3

in either cases numbers are 3,5

and smaller number is 3.

3

Step-by-step explanation:

3 squared is 9. 5 squared is 25. 25 + 9 = 34. 5 + 3 = 8. So the smaller number is 3.