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24 June, 05:21

Let the random variable x be equally likely to assume any of the values 1/12, 1/6, or 1/4. determine the mean and variance of x.

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  1. 24 June, 07:19
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    The mean of x is

    (1/3) (1/12 + 1/6 + 1/4) = 1/6

    The mean of the squares is

    (1/3) ((1/12) ² + (1/6) ² + (1/4) ²) = 7/216

    The variance is the difference between the mean square and the square of the mean.

    7/216 - (1/6) ² = 1/216

    The mean of x is 1/6.

    The variance of x is 1/216.
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