Ask Question
18 March, 00:16

2kx+4mx-2nx-3ky-6my+3ny factor by grouping

+3
Answers (1)
  1. 18 March, 01:59
    0
    2kx+4mx-2nx-3ky-6my+3ny = 2x (k+2m-n) - 3y (k+2m-n) = (2x-3y) (k+2m-n)
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “2kx+4mx-2nx-3ky-6my+3ny factor by grouping ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers