Jason empties his piggy bank and counted out exactly $10 in nickels, dimes and quarters. There were twice as many dimes as Nickels. There were twice as many quarters as dimes. How many nickels did they have?

8 nickels

Step-by-step explanation:

Total Amount of Money owned by Jason=$10

1 nickel = $0.05

1 dime=$0.10

1 quarter = $0.25

Let the number of dimes = d Let the number of nickels = n Let the number of quarters = q

If there were twice as many dimes as Nickels, then:

d=2n

Also, there were twice as many quarters as dimes.

q=2d

Therefore:

0.1d+0.05n+0.25q=100

Substituting d=2n and q=2d into the above relations

0.1 (2n) + 0.05n+0.25 (2d) = 10

0.2n+0.05n+0.25 (2 (2n)) = 10

0.2n+0.05n+1n=10

1.25n=10

n=8

q=2d=2X16=32

d=2n=2X8=16

Jason had 8 nickels