how much wrapping paper would you need to cover a rectangular that is 18.25 inches by 12inches by 3 inches if you need 10% more wrapping paper than the surface area of the box? give your answer to the nearest square inch

Answer: 681 square inch

Step-by-step explanation:

Hi, we have to apply the formula for the surface area:

A = 2wl + 2lh + 2hw

Where:

w: width

l: length

h: height

Replacing with the values given:

A = (2x12x18.25) + (2x12x3) + (2x18.25x3)

A = 438+72+109.25

A=619.5 in2

Since it has to be 10% more than the surface.

619.5 x (10/100) = 61.95 in2

Adding that value to the surface area

619.5+61.95 = 681.45in2 = 681 in2