In a triangle, if the second angle is 3 times the sum of the first angle and 3 and the third angle is the sum of 2 times the first angle and 3, find three angles of triangle.

28°, 93° and 59°

let x be the first angle then the second angle = 3 (x + 3)

and the third angle = 2x + 3

the sum of the angles in a triangle = 180°, thus

x + 3x + 9 + 2x + 3 = 180

6x + 12 = 180 (subtract 12 from both sides)

6x = 168 (divide both sides by 6)

x = 28

the angles are x = 28°, 3 (x + 3) = 93° and 2x + 3 = 59°