Ask Question
4 March, 01:28

Solve this 2 system equations 2x - y = 7 and 6x - 3y = 14

+1
Answers (2)
  1. 4 March, 03:16
    0
    No solution

    Step-by-step explanation:

    Consider the given two lines

    2x-y = 7 and 6x-3y = 14

    Multiply the first equation by 3

    6x-3y = 21 and Ii equation is 6x-3y = 14

    We observe both are of the 6x-3y = k for different ks

    Hence these two are parallel lines.

    As parallel lines never meet these line will not meet at all.

    There cannot be any solution for this system.

    If we subtract 6x-3y = 21 from 6x-3y = 14, we get absurd result as

    0 = 7

    This confirms that this system cannot be solved.
  2. 4 March, 03:26
    0
    Start by solving for one variable.

    2x-y=7

    -y=-2x+7

    y=2x-7 Plug this in for y in the other equation

    6x-3 (2x-7) = 14

    6x-6x+21=14

    21=14 This is false therefore the equations are inconsistent
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Solve this 2 system equations 2x - y = 7 and 6x - 3y = 14 ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers