Nour drove from the dead sea up to amman, and her altitude increased at a constant rate. When she began driving, her altitude was 400meters below sea level. When she arrived in amman 2 hours later, her altitude was 1000 meters above sea level. Let a (t), left parenthesis, t, right parenthesis denote nour's altitude relative to sea level a (measured in meters) as a function of time t (measured in hours).

Question

Mathematics

Rafael Ortiz

26 November, 11:03

Nour drove from the dead sea up to amman, and her altitude increased at a constant rate. When she began driving, her altitude was 400meters below sea level. When she arrived in amman 2 hours later, her altitude was 1000 meters above sea level. Let a (t), left parenthesis, t, right parenthesis denote nour's altitude relative to sea level a (measured in meters) as a function of time t (measured in hours).

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Answers (1)

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Bronson Walls · Answer 1

a (t) = 700t-400

Step-by-step explanation:

Given that when Nour drove altitude increased at a constant rate. Let us consider sea level as 0 and starting time as 0 we have

At the start t = 0 and a = - 400 m

When t=2 a = 1000 m.

Rate of change of a wrt time = change in a/Change in time

= {1000 - (-400) } / (2-0) = 700

i. e. slope = 700

a = 700 t + C

To find C:

When t = 0, a = -400

Hence C = -400

Equation is a (t) = 700t-400