If a (n) = 24 which recursive formula could represent the sequence below?

...,24,88,664,8408, ...

24 = 3*2^3

88 = 11*2^3

664 = 83*2^3 - > 83=11+72 = 11 + 2^3*3^2

664=2^3 (11+2^3*3^2) = 88 + (2^3*2^3*3^2) = 88 + (24^2)

8408 = 1051 * 2^3 - > 1051 = 83+968 - > 968 = 2^3 * 11^2

8408 = 2^3 (83+2^3*11^2) = 664 + (2^3*2^3*11^2) = 664 + (88^2)

So:

a (n) = a (n-1) + a (n-2) ^2

Lets check: 88+24^2 = 664

664+88^2 = 8408