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23 September, 12:46

For the numerator to have (x-8) as a factor, it's constant term must be what

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  1. 23 September, 15:38
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    Step-by-step explanation:

    Right now the numerator is x^2 - 10x + 14, we need to add 2 to the constant of the numerator expression to get x^2 - 10x + 16.

    For the numerator to have (x-8) as a factor, its constant term must be 16.
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