The sum of three numbers is 148. The first number is 10 less than the second. The third number is 4 times the first. What are the numbers?

Answer

1st ⇒ 23

2nd ⇒ 33

3rd ⇒ 92

Explanation

Let the 1st term = x

The 1st term is 10 less the 2nd term. So, the 2nd term = x + 10.

The third term is 4 times the 1st term. So, 3rd term = 4*x = 4x

The sum of these 3 numbers is 148.

x + (x+10) + 4x = 148

6x + 10 = 148

6x = 138

x = 23

1st ⇒ 23

2nd ⇒ 23+10 = 33

3rd ⇒ 4*23 = 92