Seth solved a quadratic equation. His work is shown below, with Step 3 missing.

What could Seth have written as the result from Step 3?

+ (x 1) 2 + 5 = 23

5 (x - 1) 2 = 18

Step 1

(x - 1) 2 = 36

Step 2

Step 3

x = - 5 or = 7

Step 4

|x - 1| = 6

Step-by-step explanation:

After step 2, we have that:

(x - 1) ^2 = 36

and after step 4, we have the results:

x = - 5 or x = 7

After step 2, what we can do in step 3 is: use square root in both sides of the equation:

|x - 1| = 6

This equation can be split in two:

x - 1 = 6 - > x = 7

x - 1 = - 6 - > x = - 5

So Seth could write this equation in step 3:

|x - 1| = 6