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16 March, 06:36

If DF=9x-39 and DE=47 and EF is 3x+10 find ef

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  1. 16 March, 08:32
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    EF = 58

    Step-by-step explanation:

    Starting with the premise that

    DF = DE + EF, then

    9x - 39 = 47 + 3x + 10 (subtract 3x from both sides)

    6x - 39 = 57 (add 39 to both sides)

    6x = 96 (divide both sides by 6)

    x = 16

    Hence

    EF = 3x + 10 = (3 * 16) + 10 = 48 + 10 = 58
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