If you have a concession stand of water for $1.50 per bottle and a concession stand with sports drinks for $2.50 per bottle, how many bottles of each drink would you need to sell to collect $100?

Question

Mathematics

James Andersen

7 April, 07:17

If you have a concession stand of water for $1.50 per bottle and a concession stand with sports drinks for $2.50 per bottle, how many bottles of each drink would you need to sell to collect $100?

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Answers (1)

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Martha Barry · Answer 1

I did a trial and error method: 30 (1.50) = $45 so I know that 60 bottles would be $90. To get the other $10, I multiplied 1.50 by 6 to get $9. So you would need to sell at least 70 bottles to get $100. You would have $0.50 over $100.

I did the same process for the sports drinks.

$2.50 (30) = $75. I now know I need to figure out how many more I need to get the other $25. So I multiplied $2.50 by 10=$25. I know that I need to sell 40 bottles of sports drinks to sell at least $100.

Final answers: 40 bottles of sports drinks and 70 bottles of water.