Choose the right answer. Plane A leaves Tulsa at 2:00 p. m., averaging 300 mph and flying in a northerly direction. Plane B leaves Tulsa at 2:30 p. m., averaging 225 mph and flying due east. At 5:00 p. m., how far apart will the planes be?

Question

Mathematics

Guest

29 May, 13:37

Choose the right answer. Plane A leaves Tulsa at 2:00 p. m., averaging 300 mph and flying in a northerly direction. Plane B leaves Tulsa at 2:30 p. m., averaging 225 mph and flying due east. At 5:00 p. m., how far apart will the planes be?

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Answers (1)

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Maria Burnett · Answer 1

Step-by-step explanation:

Average Speed = distance traveled in mile / time in hours

Plane speed = 300 mph = distance traveled by A / time

difference in time from 2:00pm to 5:00p. m = 5: p. m - 2: 00 pm = 3 hrs

distance traveled by A = speed * time = 300 * 3 = 900 miles north

Plane B

time difference = 5: 00 pm - 2:30 pm = 2.5 hrs

distance traveled by plane B = 225 * 2.5 = 562.5 miles east

to find their distance apart we use Pythagoras theorems

distance apart D = √ (900² + 562.5²) = 1061.32 miles

tanФ = 900 / 562.5

Ф = tan⁻¹ (900 / 562.5) = 57.99°