A bag contains 6 red marbles, 3 blue, and 1 yellow marble. What is the probability of drawing a red marble and then a blue marble if the first marble is not placed back into the bag before drawing the second marble?

Question

Mathematics

Akira Duncan

28 March, 09:16

A bag contains 6 red marbles, 3 blue, and 1 yellow marble. What is the probability of drawing a red marble and then a blue marble if the first marble is not placed back into the bag before drawing the second marble?

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Answers (1)

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Kyle Mosley · Answer 1

At the start, you have 10 marbles in total and 6 red marbles. The probability of the first event is 6/10.

Since you do not place the marble back in, you now have 9 marbles in total and 3 blue marbles. This probability of the second event is 3/9.

To find the probability of both events occurring, we multiply the two probabilities together. (6•3) / (10•9) = 18/90=1/5

Thus, there is a 20% chance of drawing a red marble then a blue marble without placing the red marble back in the bag.