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28 June, 23:06

An open box is formed from a rectangular piece of cardboard whose length is 8cm more than its width by cutting squares of 2cm from each corner and folding. If the volume = 256 what are the dimensionS?

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  1. 29 June, 00:03
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    If the width of the cardboard = x cm then its length is given by x + 8 cm.

    Then the length of the box will be x + 8 - 2 (2) = x + 4

    and the width = x - 2 (2) = x - 4 cm The height is 2 cm

    Volume = h*w*l = 2 (x - 4) (x + 4) = 256

    2 (x^2 - 16) = 256

    x^2 - 16 = 128

    x^2 = 144

    x = 12 cm

    Dimensions of the box are:-

    length = 12 + 4 = 16cm

    width = 12 - 4 = 8 cm

    height = 2 cm
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