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5 March, 14:54

Evaluate the integral by making the given substitution. (Use C for the constant of integration.) sin3 (θ) cos (θ) dθ, u = sin (θ) g

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  1. 5 March, 17:20
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    Evaluate int[sin^3 (θ) cos (θ) dθ] with u = sin (θ)

    du/dθ = cos (θ), dθ = du/cos (θ)

    The integral becomes:

    int[u^3•cos (θ) du/cos (θ) ]

    = int[u^3•du]

    = u^4/4 + C

    Substitute u = sin (θ) to get back a function of θ:

    sin^4 (θ) / 4 + C
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