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3 April, 12:51

Calculator question.

Whats is the minimum window that allows r^2=4cos (2theta)

multiple choice

A. [0,2pi]

B. [0, pi]

C. [-2pi, 2pi]

D [0, pi/2]

+3
Answers (1)
  1. 3 April, 15:07
    0
    D. [0, pi/2]

    Step-by-step explanation:

    when Ф = 0 in radian

    r² = 4cos (2 (0))

    r² = 4 * 1

    r² = 4

    ∴ r = √4 = 2

    r = 2.

    when Ф = π/2 in radian

    r² = 4cos (2 (π/2))

    r² = 4 * - 1

    r² = - 4

    ∴ r = 0
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