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13 June, 15:27

What is the result of isolating x^2 in the equation below (x+1) ^2 + (y-8) ^2=9

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Answers (2)
  1. 13 June, 18:15
    0
    x² = 8 - (y - 8) ² - 2x

    x² = 16y - y² - 2x - 56

    Step-by-step explanation:

    ∵ (x + 1) ² + (y - 8) ² = 9

    ∵ x² + 2x + 1 = 9 - (y - 8) ²

    ∴ x² = 9 - (y - 8) ² - 2x - 1

    ∴ x² = 8 - (y - 8) ² - 2x

    OR:

    ∵ x² = 8 - (y² - 16y + 64) - 2x

    ∴ x² = 8 - y² + 16y - 64 - 2x

    ∴ x² = 16y - y² - 2x - 56
  2. 13 June, 18:26
    0
    x² = 16y-y²-2x-56

    Step-by-step explanation:

    We have given the equation:

    (x+1) ² + (y-8) ²=9

    We have to solve it for x².

    So, the above equation is:

    (x+1) ² + (y-8) ²=9

    Open the square of the terms we get,

    x²+1+2x+y²+64-16y = 9

    x²+2x+y²-16y+65 = 9

    The equation in terms of x² is:

    x² = 9-2x-y²+16y-65

    x² = 16y-y²-2x-56 is the answer.
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