A nuclear power plant has two independent safety systems. The probability the first will not operate properly in an emergency P (A) is 0.01, and the probability the second will not operate P (B) in an emergency is 0.03. What is the probability that in an emergency both of the safety systems will not operate?

A. 3

B. 0.03

C. 0.0003

D. None of the choices are correct

Question

Mathematics

Olivia Walter

26 October, 10:41

A nuclear power plant has two independent safety systems. The probability the first will not operate properly in an emergency P (A) is 0.01, and the probability the second will not operate P (B) in an emergency is 0.03. What is the probability that in an emergency both of the safety systems will not operate?

A. 3

B. 0.03

C. 0.0003

D. None of the choices are correct

+3

Answers (2)

Know the Answer?

Wags · Answer 1

The systems are independent and function independently. The joint probability in question is 0.01*0.03 = 0.0003.

Karson Chapman · Answer 2

Each system is independent of one another, so you multiply the probabilities of failure for each

P (A and B) = P (A) * P (B)

P (A and B) = 0.01*0.03

P (A and B) = 0.0003

Answer: Choice C