the length of a rectangle is 2cm more than four times the width. if the perimeter of the rectangle is 84 cm, what are it's dimensions?

w=8 L = 34

Step-by-step explanation:

P=2W+2L

L=4W+2

2W + 2 (4W+2) = 84

2W + 8W + 4 = 84

10W=80

w=8

L = (8*4+2) = 34

2 (8) + 2 (34) = 16 + 68 = 84

x=36; y=8.

Step-by-step explanation:

x=length

y=width

the length of a rectangle is 2cm more than four times the width.

so,

x=2+4y ... (1)

now,

the perimeter of the rectangle is 84 cm

so,

2 (x+y) = 84

x+y=42 ... (2)

2+4y+y=42

5y=40

y=8 ... (3)

so,

x=42-8 [from 2 & 3]

x=36