A^2+10a+24 does anyone know how to do it

(a + 4) (a + 6)

Step-by-step explanation:

f (a) = a² + 10a + 24

I think you are asking us to factor the quadratic.

1. Multiply the leading coefficient and the constant

1 * 24 = 24

2. Find two numbers that multiply to give 24 and add to give 10.

Possible pairs are 1, 24; 2, 12; 3, 8; 4, 6

Start with the numbers near the end of the list.

By trial and error, you will find that 4 and 6 work:

4 * 6 = 24 and 4 + 6 = 10

3. Rewrite 10a as 4a + 6a

a² + 4a + 6a + 24

4. Factor by grouping the first two and the last two terms

a (a + 4) + 6 (a + 4)

5. Distribute the a + 4

(a + 4) (a + 6)

a² + 10a + 24 = (a + 4) (a + 6)