Find the first five terms of the geometric sequence whose constant ratio is - 5 and whose first term is 6.

Answer: 6,-30,150,-750,3750

Step-by-step explanation:

Geometric progression formula is

An=a1r^ (n-1)

An = nth term

A1 = first term

R = common ratio

N = nth position

A1=6

R=-5

We already know the first term, looking for 2nd 3rd 4th & 5th

A2=a1r^ (n-1)

A2=6 * (-5^ (2-1))

A2=6 * (-5^1)

A2=6*-5

A2 = - 30

A3=a1r^ (n-1)

A3=6 * (-5^ (3-1))

A3=6 * (-5^ (2))

A3=6 * (25)

A3 = 150

A4=a1r^ (n-1)

A4=6 * (-5^ (4-1))

A4=6 * (-5^3)

A4=6*-125

A4 = - 750

A5=a1r^ (n-1)

A5=6 * (-5^ (5-1))

A5=6 * (-5^ (4))

A5=6 * (625)

A5=3750

The first 5 numbers are

6,-30,150,-750,3750

Answer: 6, - 30, 150, - 750 and 3750.

Step-by-step explanation:

First term = 6

Second term = ar = 6 * (-5) = - 30

Third term = ar^2 = 6 * (-5) (-5) = 150

Forth term = ar^3 = 6 * (-5) ^3 = - 750

Fifth term = ar^4 = 6 * (-5) ^4 = 3750