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5 January, 12:06

4. A rock is thrown with a height equation of h = - 16t2 + 64t + 5 (where h is the height of the rock in feet at any given time of t in seconds). Will it reach a height of 50 feet? Explain your answer.

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  1. 5 January, 15:58
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    Yes, see below.

    Step-by-step explanation:

    Convert the equation to vertex form to find the maximum height:

    h = - 16t2 + 64t + 5

    = - 16 (t^2 - 4t) + 5

    = - 16 [ (t - 2) ^2 - 4] + 5

    = - 16 (t - 2) ^2 + 64 + 6

    = - 16 (t - 2) ^2 + 69.

    So the maximum height the rock reaches is 69 feet.

    This height is reached at 2 time seconds.
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