A parabola has x-int of (-8,0) and (4,0) and a minimum value of - 9 in intercept form

The function is 1/4x^2 + x - 8

Step-by-step explanation:

In Factor form the function is

a (x + 8) (x - 4) where a is a constant to be found.

= a (x^2 + 4x - 32) Note the coefficient of x is positive because the function has a minimum value.

The line of symmetry is x = (-8+4) / 2 = - 2.

So the minimum value will be the value of f (x) when x = - 2, so we have the equation

a (-2+8) (-2-4) = - 9

-36a = - 9

a = 1/4.