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31 December, 19:30

What is the solution set for this linear quadratic system of equations

y=*2-*-12. y-*-3=0

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  1. 31 December, 23:16
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    1. rearrange equation (step only used when necessary)

    -> 2x-x-12=y, y = x+3 (I subtracted the Y from both sides and then divided everything by - 1 to get rid of the number.

    2. then you can solve with the equations equaling each other

    -> 2x-x-12=x+3
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