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2 December, 23:36

One year ago, a man was 8 times as old as his son. Now his age is equal to the square of his sons age. The present age of son is

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  1. 3 December, 00:11
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    The present age of son is 7

    Step-by-step explanation:

    Let the son age be x

    One year ago

    Son's age = x - 1

    Therefore man's age = 8 (x-1) = 8x - 8

    Now man's age = x^2

    Difference between both ages if man = 1 years

    So

    x^2 - (8x-8) = 1

    x^2-8x + 8-1 = 0

    x^2 - 8x + 7 = 0

    x^2 - 7x - x + 7 = 0

    X (x-7) - 7 (x - 7) = 0

    (x - 1) (x - 7) = 0

    x = 1, 7

    But son cannot be 1 years

    Therefore,

    x = 7

    SO,

    age of son is 7

    age of father is x*7=49
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