One number is 8 more than another number, and their sum is 20. Find the numbers.

The numbers are

and

The numbers are 6 and 14

Step-by-step explanation:

Say the unknown numbers are x and y

Say y = 8+x ... eqn 1

and x + y = 20 ... eqn 2

Then if you replace y by 8+x, eqn 1 becomes

x + 8 + x = 20

Collect the like terms

x + x = 20 - 8

2x = 12

Divide both sides by 2

x = 12/6

x = 6

Then to get y, substitute 6 for x in eqn 1, and we will have

y = 8 + 6

y = 14

First number=6

Second number=14

Step-by-step explanation:

Let the first number be x

So the second number is x+8

So the sum of the two is

X+x+8=20

2x+8=20

2x=20-8

2x=12

X=12/2

=6

The second number will x+8

So 6+8=14

First number=6

Second number=14