The sum of 3 consecutive odd integers is 87. Find the equation used to solve this problem and the three integers.

The first odd integer is x. The next odd integer will be x+2. and the next is x+4. Then we can say that (x) + (x+2) + (x+4) = 87

working that out yields 3x+6=87

and thus 3x=81

and by consequence x=27

and thus our 3 odd integers are 27,29 and 31

Let be y - 2, y and y + 2 the 3 consecutives odd integers;

There sum is 3y, and, in the same time is 87 = > y = 87/3 = > y = 29 = >

y - 2 = 27; y + 2 = 31;

The 3 integers are : 27, 29, 31.