A 2X2 square is centered at the origin. It is dilated by a factor of 3. What are coordinates of the vertices of the square?

The vertices are:

A' = (-3, - 3)

B' = (3, - 3)

C' = (3, 3)

D' = (-3, 3)

Step-by-step explanation:

Given:

A 2 x 2 square is centered at the origin.

So, the center of the square is (0, 0)

Since it is 2 x 2 square, the side of the square is 2 units.

So, the vertices of the 2 x 2 square are A (-1, - 1), B (1, - 1), C (1. 1), D (-1, 1)

The above square is dilated by a factor of 3.

Let's name the dilated square A'B'C'D'

To find the coordinates of the vertices of dilated square, we need to multiply each vertices of ABCD by 3.

A (-1, - 1) = 3 (-1, - 1) = A' (-3, - 3)

B (1, - 1) = 3 (1, - 1) = B' (3, - 3)

C (1, 1) = 3 (1, 1) = C' (3, 3)

D (-1, 1) = 3 (-1, 1) = D' (-3, 3)