Multiply each equation by a number that producess opposite coefficients for x and y?

4x+5y=7

3x-2y=-12

(number between = 5 and 5 for both)

Let's solve your system by substitution.

3x-2y=-12; 4x+5y=7

Step: Solve3x-2y=-12for x:

3x-2y=-12

3x-2y+2y=-12+2y (Add 2y to both sides)

3x = 2y-12

3 3

=

2y-12

3

(Divide both sides by 3)

x=

2

3 y-4

Step: Substitute

2

3

y-4 for x in 4x+5y=7:

4x+5y=7

4 (2/3 y-4) + 5y=7

23

3

y-16=7 (Simplify both sides of the equation)

23

3

y-16+16=7+16 (Add 16 to both sides)

23

3

y=23

23

3 y

23

3 = 23

23

3

(Divide both sides by 23/3)

y=3

Step: Substitute 3 for y in x=

2

3 y-4:

x=

2

3 y-4

x = 2

3 (3) - 4

x=-2 (Simplify both sides of the equation)

Answer:

x=-2 and y=3 (underlined and / are fractions or division)