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12 August, 12:11

Factor 12q^2+34q-28. Include list of factors.

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Answers (1)
  1. 12 August, 12:57
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    2 (2q+7) (3q-2) = 0

    Step-by-step explanation:

    lets set up the equation equal to 0:

    12q^2+34q-28=0

    now, lets factor:

    2 (6q^2+17q-14) = 0

    2 (2q+7) (3q-2) = 0

    now, lets find the solutions:

    2q+7=0

    2q=-7

    q=-3.5

    3q-2=0

    3q=2

    q=2/3
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