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11 September, 16:40

A store sells the basic model of a phone for $60 and the upgraded model for $200. It costs the store $10 to buy each basic

model and $50 to buy each upgraded model from the phone company. On Tuesday, the store has $1,800 in sales for these

two models, and it paid the phone company $400 to buy these phones. How many upgraded models did the store sell on

Tuesday?

6 upgraded phones

10 upgraded phones

15 upgraded phones

42 upgraded phones

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Answers (2)
  1. 11 September, 19:06
    0
    6 upgraded phones

    Step-by-step explanation:

    Let the number of basic model phones sold on Tuesday be "x" and the number of upgraded model phones be "y".

    Sale price of each basic model phones is $60, so the sale price of x basic model phones will be $ 60x

    Sale price of each upgraded model phones is $200, so the Sale price of y basic model phones will be $ 200y

    On Tuesday, the store has $ 1800 in sales. This was the sales from x basic model and y upgraded model phones. So, based on the above data, we can set up the equation as:

    60x + 200y = 1800 Equation 1

    Cost of each basic model phones is $10 so the cost of x basic model phones will be $ 10x

    Cost of each upgraded model phones is $50, so the cost of y basic model phones will be $ 50y

    The store paid $400 to buy these x basic model and y upgraded phones. So, based on the above data, we can set up another equation as:

    10x + 50y = 400 Equation 2

    Multiplying the Equation 2 by 6 and subtracting it from Equation 1 we get:

    60x + 200y - 6 (10x + 50y) = 1800 - 6 (400)

    60x + 200y - 60x - 300y = 1800 - 2400

    - 100y = - 600

    y = 6

    Since, y represents the number of upgraded phones, we can conclude that the store sold 6 upgraded phones on Tuesday.
  2. 11 September, 19:47
    0
    Simple Answer - 6 upgraded phones
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