2x - y = 5 3x + 2y = 4 Solve the system of equations. A) (3, 1) B) (0, 2) C) (2, - 1) D) (9 7, 17 7)

Solve the system with elimination

multiply the first equation by two to cancel

2 (2x-y=5) new equation 4x-2y=10

now the - 2y and 2y cancel each other out

now you have 4x=10 + 3x=4 = 7x=14

divide by 7 to get x=2 now we have to find y by plugging x into one of the equations (let's use the first one)

2 (2) - y=5 - -> 4-y=5 - -> - y = 1 - -> y = -1

(x, y) (2,-1)