Which system of equations has a solution of approximately (1.8,-0.9)

A. 6x-5y=15 and x+2y = 0

B. 4x+5y=8 and 6x-5y=15

C. x-2y=4 and 4x+5y=8

D. 6x-5y=15 and x-2y=4

A.

6x - 5y = 15

L = 6 (1.8) - 5 (-0.9) = 10.8 + 4.5 = 15.3

R = 15

L ≈ R

x + 2y = 0

L = 1.8 + 2 (-0.9) = 1.8 - 1.8 = 0

L = R

B.

4x + 5y = 8

L = 4 (1.8) + 5 (-0.9) = 7.2 - 4.5 = 2.7

R = 8

L ≠ R

C.

x - 2y = 4

L = 1.8 - 2 (-0.9) = 1.8 + 1.8 = 3.6

R = 4

L ≈ R

4x + 5y = 8

L = 4 (1.8) + 5 (-0.9) = 7.2 - 4.5 = 2.7

R = 8

L ≠ R

D.

6x - 5y = 15

L = 6 (1.8) - 5 (-0.9) = 10.8 + 4.5 = 15.3

R = 15

L ≈ R

x - 2y = 4

L = 1.8 - 2 (-0.9) = 1.8 + 1.8 = 3.6

R = 4

L ≈ R

Yeah so your answer is gonna be

A.

Solve the equation systems or set the values x = 1.8 and y = - 0.9 on the equation and check the equality.

A.

6x - 5y = 15

L = 6 (1.8) - 5 (-0.9) = 10.8 + 4.5 = 15.3

R = 15

L ≈ R

x + 2y = 0

L = 1.8 + 2 (-0.9) = 1.8 - 1.8 = 0

L = R

B.

4x + 5y = 8

L = 4 (1.8) + 5 (-0.9) = 7.2 - 4.5 = 2.7

R = 8

L ≠ R

C.

x - 2y = 4

L = 1.8 - 2 (-0.9) = 1.8 + 1.8 = 3.6

R = 4

L ≈ R

4x + 5y = 8

L = 4 (1.8) + 5 (-0.9) = 7.2 - 4.5 = 2.7

R = 8

L ≠ R

D.

6x - 5y = 15

L = 6 (1.8) - 5 (-0.9) = 10.8 + 4.5 = 15.3

R = 15

L ≈ R

x - 2y = 4

L = 1.8 - 2 (-0.9) = 1.8 + 1.8 = 3.6

R = 4

L ≈ R

We have two probability solutions: A and D.

But I think, Your answer is A.