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15 July, 18:35

Find the approximate value of each trigonometric function.

Given that sin0 = 0.312 where - <0 Since 0 lies in Quadrant II, where cos0 <0, cos is approximately

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  1. 15 July, 18:57
    0
    -0.95

    Step-by-step explanation:

    cos (theta) = sqrt (1 - sin² (theta))

    = sqrt (1 - 0.312²)

    = sqrt (0.902656)

    = + / - 0.9500821017

    Since cos is negative in quadrant 2,

    cos (theta) = - 0.95
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